6/19/2023 0 Comments Unrar windows![]() I suggest to build the command line while reading it and test the command line first from within a command prompt window. The manual is text file Rar.txt in program files folder of WinRAR which you should read from top to bottom. Last but not least there is a complete manual for Rar.exe which of course can also extract files and folders from a RAR archive which makes additional usage of UnRAR.exe useless. Also UnRAR.exe outputs a brief help if executed without any parameter. P.StartInfo.Arguments = "x -p" pw " PL_LOCKED_ARCHIVE.rar" įurther all commands and switches of console version Rar.exe are briefly explained when simply running Rar.exe without any parameter in a command prompt window. P.StartInfo.FileName = Files\WinRAR\UnRAR.exe" P.StartInfo.Arguments = "a -p" pw " PL_LOCKED_ARCHIVE.rar " fld P.StartInfo.FileName = Files\WinRAR\Rar.exe" So first of all you need to correct StartInfo: void LOCK(string fld, string pw) The result is most likely an error message because of invalid command rar respectively unrar as the first argument must be a or x for WinRAR.exe. ![]() That is of course wrong as you do not want to run WinRAR.exe with first argument being a reference to console version Rar.exe or UnRAR.exe. The StartInfo you define results in running WinRAR.exe with command line: C:\Program Files\WinRAR\WinRAR.exe unrar x -p pw PL_LOCKED_ARCHIVE.rar ![]()
0 Comments
Leave a Reply. |